Molar MassMolar mass of aniline (C6H5NH2)
The molar mass of aniline, C6H5NH2, is 93.13 g/mol. One mole of it, which is 6.022 × 1023 molecules, has a mass of 93.13 grams.
93.13 g/mol
6 × 12.011 + 7 × 1.0080 + 14.007 = 93.129 · 14 atoms in the formula · also called phenylamine, aminobenzene
About aniline
Aniline is the simplest aromatic amine and the starting point for many dyes.
Other names: phenylamine, aminobenzene.
The working
The formula C6H5NH2 has 6 carbon atoms, 7 hydrogen atoms and 1 nitrogen atom, 14 atoms in all. Multiply each count by the atomic weight of the element and add:
| Element | Atoms | Atomic weight | Total | Share by mass |
|---|---|---|---|---|
| Carbon (C) | 6 | 12.011 | 72.066 | 77.38% |
| Hydrogen (H) | 7 | 1.0080 | 7.056 | 7.58% |
| Nitrogen (N) | 1 | 14.007 | 14.007 | 15.04% |
6 × 12.011 + 7 × 1.0080 + 14.007 = 93.129 g/mol
With the rounded atomic masses used in many school books (C = 12, H = 1, N = 14) the answer is 93 g/mol. The difference from 93.13 is too small to matter in most school sums.
Percentage composition
By mass, C6H5NH2 is 77.38% carbon, 7.58% hydrogen and 15.04% nitrogen. The largest share comes from carbon. In a 100 g sample there are 77.4 g of carbon, 7.6 g of hydrogen and 15.0 g of nitrogen.
Notice that hydrogen has more atoms in the formula (7) than carbon (6), yet gives a smaller share of the mass. Percentage by mass depends on how heavy each atom is, not only on how many there are.
Worked examples
Grams to moles. How many moles are in 40 g of C6H5NH2? Divide the mass by the molar mass: 40 ÷ 93.13 = 0.4295 mol.
Moles to grams. What is the mass of 3 mol of C6H5NH2? Multiply: 3 × 93.13 = 279.4 g.
Counting particles. 40 g contains 0.4295 mol × 6.022 × 1023 = 2.587 × 1023 molecules, and 3.621 × 1024 atoms in all.
Quick conversion tables
| Amount | Mass |
|---|---|
| 0.1 mol | 9.313 g |
| 0.5 mol | 46.56 g |
| 1 mol | 93.13 g |
| 2 mol | 186.3 g |
| 5 mol | 465.6 g |
| Mass | Moles |
|---|---|
| 1 g | 0.01074 mol |
| 10 g | 0.1074 mol |
| 100 g | 1.074 mol |
| 1 kg | 10.74 mol |
For other amounts use the grams and moles converter.
Questions people ask
What is the molar mass of C6H5NH2?
The molar mass of aniline (C6H5NH2) is 93.13 g/mol, or 93.129 g/mol before rounding, using IUPAC abridged atomic weights.
How many moles are in 100 g of C6H5NH2?
100 ÷ 93.13 = 1.074 mol.
What is the mass of one molecule of C6H5NH2?
Divide the molar mass by the Avogadro constant: 93.13 ÷ 6.022 × 1023 = 1.546 × 10-22 g.
What is the percentage of carbon in C6H5NH2?
Carbon makes up 77.38% of the mass of C6H5NH2: 6 × 12.011 ÷ 93.129 × 100.
Which values? This site uses the abridged standard atomic weights published by IUPAC (CIAAW), read on 12 November 2026. Your textbook or question paper may round them differently, for example H = 1 and O = 16, so its answer can differ slightly. In an exam, use the values the paper gives.