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Molar mass of potassium carbonate (K2CO3)

The molar mass of potassium carbonate, K2CO3, is 138.20 g/mol. One mole of it, which is 6.022 × 1023 formula units, has a mass of 138.20 grams.

138.20 g/mol

2 × 39.098 + 12.011 + 3 × 15.999 = 138.204 · 6 atoms in the formula · also called potash, pearl ash

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About potassium carbonate

Potassium carbonate was first obtained from wood ash, which gave potassium its name. It is used in making soap and hard glass.

Other names: potash, pearl ash.

The working

The formula K2CO3 has 2 potassium atoms, 1 carbon atom and 3 oxygen atoms, 6 atoms in all. Multiply each count by the atomic weight of the element and add:

ElementAtomsAtomic weightTotalShare by mass
Potassium (K)239.09878.19656.58%
Carbon (C)112.01112.0118.69%
Oxygen (O)315.99947.99734.73%

2 × 39.098 + 12.011 + 3 × 15.999 = 138.204 g/mol

With the rounded atomic masses used in many school books (K = 39, C = 12, O = 16) the answer is 138 g/mol. The difference from 138.20 is too small to matter in most school sums.

Percentage composition

By mass, K2CO3 is 56.58% potassium, 8.69% carbon and 34.73% oxygen. The largest share comes from potassium. In a 100 g sample there are 56.6 g of potassium, 8.7 g of carbon and 34.7 g of oxygen.

Worked examples

Grams to moles. How many moles are in 100 g of K2CO3? Divide the mass by the molar mass: 100 ÷ 138.20 = 0.7236 mol.

Moles to grams. What is the mass of 2 mol of K2CO3? Multiply: 2 × 138.20 = 276.4 g.

Counting particles. 100 g contains 0.7236 mol × 6.022 × 1023 = 4.357 × 1023 formula units.

Making a solution. A 0.1 mol/L solution contains 0.1 × 138.20 = 13.82 g of K2CO3 in each litre. For 250 mL, weigh 3.455 g and make it up to the mark with water.

Quick conversion tables

AmountMass
0.1 mol13.82 g
0.5 mol69.1 g
1 mol138.2 g
2 mol276.4 g
5 mol691 g
MassMoles
1 g0.007236 mol
10 g0.07236 mol
100 g0.7236 mol
1 kg7.236 mol

For other amounts use the grams and moles converter.

Questions people ask

What is the molar mass of K2CO3?

The molar mass of potassium carbonate (K2CO3) is 138.20 g/mol, or 138.204 g/mol before rounding, using IUPAC abridged atomic weights.

How many moles are in 100 g of K2CO3?

100 ÷ 138.20 = 0.7236 mol.

What is the mass of one formula unit of K2CO3?

Divide the molar mass by the Avogadro constant: 138.20 ÷ 6.022 × 1023 = 2.295 × 10-22 g.

What is the percentage of potassium in K2CO3?

Potassium makes up 56.58% of the mass of K2CO3: 2 × 39.098 ÷ 138.204 × 100.

Which values? This site uses the abridged standard atomic weights published by IUPAC (CIAAW), read on 12 November 2026. Your textbook or question paper may round them differently, for example H = 1 and O = 16, so its answer can differ slightly. In an exam, use the values the paper gives.

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