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Frustum of a cone

A frustum of a cone is what remains when the top of a cone is cut off by a slice parallel to the base. It has two circular ends of different sizes. A bucket is the everyday example.

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Formulas

  • Slant height l = √(h2 + (R − r)2)
  • Volume = ⅓ πh(R2 + Rr + r2)
  • Curved surface area = π(R + r)l
  • Total surface area = π(R + r)l + π(R2 + r2)

R = larger radius, r = smaller radius and h = height.

Properties

Why the formulas work

A frustum is a big cone with a small cone removed from its top. The two cones are similar, and subtracting their volumes and tidying the algebra gives ⅓πh(R² + Rr + r²). The curved surface is found the same way, by subtracting the curved surfaces of the two cones, and comes to π(R + r)l.

Worked example

Take a frustum of a cone with larger radius 14 cm, smaller radius 7 cm and height 24 cm.

  1. Slant height. Slant height l = √(h2 + (R − r)2). Here: √(24² + (14 − 7)²) = 25 cm.
  2. Volume. Volume = ⅓ πh(R2 + Rr + r2). Here: ⅓ × π × 24 × (14² + 14 × 7 + 7²) = 8,620.53 cm³ (with π = 22/7: 8,624 cm³).
  3. Curved surface area. Curved surface area = π(R + r)l. Here: π × (14 + 7) × 25 = 1,649.34 cm² (with π = 22/7: 1,650 cm²).
  4. Total surface area. Total surface area = π(R + r)l + π(R2 + r2). Here: 1,649.34 + π × (14² + 7²) = 2,419.03 cm² (with π = 22/7: 2,420 cm²).

Finding a missing measurement

If the slant height is given and not the height, h = √(l² − (R − r)²): radii of 14 cm and 7 cm with a slant height of 25 cm give h = √(625 − 49) = 24 cm. For a bucket, the capacity in litres is the volume in cm³ divided by 1000.

Mistakes to avoid

Where you see it

Buckets, drinking glasses, flower pots, lampshades and funnels (the wide part) are frustums.

Try these

Work each one out, then tap to check.

A frustum of a cone has larger radius 10 cm, smaller radius 4 cm and height 8 cm. Find its slant height, volume, curved surface area and total surface area. Take π = 22/7.

Slant height = 10 cm; Volume = 1,307.43 cm³; Curved surface area = 440 cm²; Total surface area = 804.57 cm².

A frustum of a cone has larger radius 20 cm, smaller radius 8 cm and height 16 cm. Find its slant height, volume, curved surface area and total surface area. Take π = 22/7.

Slant height = 20 cm; Volume = 10,459.43 cm³; Curved surface area = 1,760 cm²; Total surface area = 3,218.29 cm².

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