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Molar mass of iodine (I2)

The molar mass of iodine, I2, is 253.80 g/mol. One mole of it, which is 6.022 × 1023 molecules, has a mass of 253.80 grams.

253.80 g/mol

2 × 126.90 = 253.800 · 2 atoms in the formula

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About iodine

Iodine forms shiny grey-black crystals that turn straight into a violet vapour when warmed. It is listed here with the other two-atom elements.

The working

The formula I2 has 2 iodine atoms. Multiply each count by the atomic weight of the element and add:

ElementAtomsAtomic weightTotalShare by mass
Iodine (I)2126.90253.800100.00%

2 × 126.90 = 253.800 g/mol

With the rounded atomic masses used in many school books (I = 127) the answer is 254 g/mol. The difference from 253.80 is too small to matter in most school sums.

Percentage composition

I2 contains only iodine, so iodine makes up 100% of its mass. Each molecule has 2 atoms, which is why the molar mass is 2 times the atomic weight 126.90.

Worked examples

Grams to moles. How many moles are in 5 g of I2? Divide the mass by the molar mass: 5 ÷ 253.80 = 0.0197 mol.

Moles to grams. What is the mass of 0.25 mol of I2? Multiply: 0.25 × 253.80 = 63.45 g.

Counting particles. 5 g contains 0.0197 mol × 6.022 × 1023 = 1.186 × 1022 molecules, and 2.373 × 1022 atoms in all.

Quick conversion tables

AmountMass
0.1 mol25.38 g
0.5 mol126.9 g
1 mol253.8 g
2 mol507.6 g
5 mol1269 g
MassMoles
1 g0.00394 mol
10 g0.0394 mol
100 g0.394 mol
1 kg3.94 mol

For other amounts use the grams and moles converter.

Questions people ask

What is the molar mass of I2?

The molar mass of iodine (I2) is 253.80 g/mol, or 253.800 g/mol before rounding, using IUPAC abridged atomic weights.

How many moles are in 100 g of I2?

100 ÷ 253.80 = 0.394 mol.

What is the mass of one molecule of I2?

Divide the molar mass by the Avogadro constant: 253.80 ÷ 6.022 × 1023 = 4.214 × 10-22 g.

Which values? This site uses the abridged standard atomic weights published by IUPAC (CIAAW), read on 12 November 2026. Your textbook or question paper may round them differently, for example H = 1 and O = 16, so its answer can differ slightly. In an exam, use the values the paper gives.

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