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Molar mass of potassium sulphate (K2SO4)

The molar mass of potassium sulphate, K2SO4, is 174.25 g/mol. One mole of it, which is 6.022 × 1023 formula units, has a mass of 174.25 grams.

174.25 g/mol

2 × 39.098 + 32.06 + 4 × 15.999 = 174.252 · 7 atoms in the formula · also called sulphate of potash

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About potassium sulphate

Potassium sulphate is a fertiliser that supplies potassium without chloride, which suits crops such as tobacco and some fruits.

Other names: sulphate of potash.

The working

The formula K2SO4 has 2 potassium atoms, 1 sulphur atom and 4 oxygen atoms, 7 atoms in all. Multiply each count by the atomic weight of the element and add:

ElementAtomsAtomic weightTotalShare by mass
Potassium (K)239.09878.19644.88%
Sulphur (S)132.0632.06018.40%
Oxygen (O)415.99963.99636.73%

2 × 39.098 + 32.06 + 4 × 15.999 = 174.252 g/mol

With the rounded atomic masses used in many school books (K = 39, S = 32, O = 16) the answer is 174 g/mol. The difference from 174.25 is too small to matter in most school sums.

Percentage composition

By mass, K2SO4 is 44.88% potassium, 18.40% sulphur and 36.73% oxygen. The largest share comes from potassium. In a 100 g sample there are 44.9 g of potassium, 18.4 g of sulphur and 36.7 g of oxygen.

Worked examples

Grams to moles. How many moles are in 50 g of K2SO4? Divide the mass by the molar mass: 50 ÷ 174.25 = 0.2869 mol.

Moles to grams. What is the mass of 0.4 mol of K2SO4? Multiply: 0.4 × 174.25 = 69.7 g.

Counting particles. 50 g contains 0.2869 mol × 6.022 × 1023 = 1.728 × 1023 formula units.

Making a solution. A 0.1 mol/L solution contains 0.1 × 174.25 = 17.43 g of K2SO4 in each litre. For 250 mL, weigh 4.356 g and make it up to the mark with water.

Quick conversion tables

AmountMass
0.1 mol17.43 g
0.5 mol87.13 g
1 mol174.3 g
2 mol348.5 g
5 mol871.3 g
MassMoles
1 g0.005739 mol
10 g0.05739 mol
100 g0.5739 mol
1 kg5.739 mol

For other amounts use the grams and moles converter.

Questions people ask

What is the molar mass of K2SO4?

The molar mass of potassium sulphate (K2SO4) is 174.25 g/mol, or 174.252 g/mol before rounding, using IUPAC abridged atomic weights.

How many moles are in 100 g of K2SO4?

100 ÷ 174.25 = 0.5739 mol.

What is the mass of one formula unit of K2SO4?

Divide the molar mass by the Avogadro constant: 174.25 ÷ 6.022 × 1023 = 2.894 × 10-22 g.

What is the percentage of potassium in K2SO4?

Potassium makes up 44.88% of the mass of K2SO4: 2 × 39.098 ÷ 174.252 × 100.

Which values? This site uses the abridged standard atomic weights published by IUPAC (CIAAW), read on 12 November 2026. Your textbook or question paper may round them differently, for example H = 1 and O = 16, so its answer can differ slightly. In an exam, use the values the paper gives.

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