Molar mass of carbon tetrachloride (CCl4)
The molar mass of carbon tetrachloride, CCl4, is 153.81 g/mol. One mole of it, which is 6.022 × 1023 molecules, has a mass of 153.81 grams.
153.81 g/mol
12.011 + 4 × 35.45 = 153.811 · 5 atoms in the formula · also called tetrachloromethane
About carbon tetrachloride
Carbon tetrachloride is a dense liquid that does not burn. It was used in fire extinguishers and dry cleaning before its dangers were understood.
Other names: tetrachloromethane.
The working
The formula CCl4 has 1 carbon atom and 4 chlorine atoms, 5 atoms in all. Multiply each count by the atomic weight of the element and add:
| Element | Atoms | Atomic weight | Total | Share by mass |
|---|---|---|---|---|
| Carbon (C) | 1 | 12.011 | 12.011 | 7.81% |
| Chlorine (Cl) | 4 | 35.45 | 141.800 | 92.19% |
12.011 + 4 × 35.45 = 153.811 g/mol
With the rounded atomic masses used in many school books (C = 12, Cl = 35.5) the answer is 154 g/mol. The difference from 153.81 is too small to matter in most school sums.
Percentage composition
By mass, CCl4 is 7.81% carbon and 92.19% chlorine. The largest share comes from chlorine. In a 100 g sample there are 7.8 g of carbon and 92.2 g of chlorine.
Worked examples
Grams to moles. How many moles are in 5 g of CCl4? Divide the mass by the molar mass: 5 ÷ 153.81 = 0.03251 mol.
Moles to grams. What is the mass of 0.25 mol of CCl4? Multiply: 0.25 × 153.81 = 38.45 g.
Counting particles. 5 g contains 0.03251 mol × 6.022 × 1023 = 1.958 × 1022 molecules, and 9.788 × 1022 atoms in all.
Quick conversion tables
| Amount | Mass |
|---|---|
| 0.1 mol | 15.38 g |
| 0.5 mol | 76.91 g |
| 1 mol | 153.8 g |
| 2 mol | 307.6 g |
| 5 mol | 769.1 g |
| Mass | Moles |
|---|---|
| 1 g | 0.006501 mol |
| 10 g | 0.06501 mol |
| 100 g | 0.6501 mol |
| 1 kg | 6.501 mol |
For other amounts use the grams and moles converter.
Questions people ask
What is the molar mass of CCl4?
The molar mass of carbon tetrachloride (CCl4) is 153.81 g/mol, or 153.811 g/mol before rounding, using IUPAC abridged atomic weights.
How many moles are in 100 g of CCl4?
100 ÷ 153.81 = 0.6501 mol.
What is the mass of one molecule of CCl4?
Divide the molar mass by the Avogadro constant: 153.81 ÷ 6.022 × 1023 = 2.554 × 10-22 g.
What is the percentage of chlorine in CCl4?
Chlorine makes up 92.19% of the mass of CCl4: 4 × 35.45 ÷ 153.811 × 100.
Which values? This site uses the abridged standard atomic weights published by IUPAC (CIAAW), read on 12 November 2026. Your textbook or question paper may round them differently, for example H = 1 and O = 16, so its answer can differ slightly. In an exam, use the values the paper gives.