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Molar mass of potassium chlorate (KClO3)

The molar mass of potassium chlorate, KClO3, is 122.55 g/mol. One mole of it, which is 6.022 × 1023 formula units, has a mass of 122.55 grams.

122.55 g/mol

39.098 + 35.45 + 3 × 15.999 = 122.545 · 5 atoms in the formula

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About potassium chlorate

Potassium chlorate gives off oxygen when heated, faster with manganese dioxide as a catalyst. This is the usual laboratory preparation of oxygen and a common source of mole questions. It is used in matches.

The working

The formula KClO3 has 1 potassium atom, 1 chlorine atom and 3 oxygen atoms, 5 atoms in all. Multiply each count by the atomic weight of the element and add:

ElementAtomsAtomic weightTotalShare by mass
Potassium (K)139.09839.09831.91%
Chlorine (Cl)135.4535.45028.93%
Oxygen (O)315.99947.99739.17%

39.098 + 35.45 + 3 × 15.999 = 122.545 g/mol

With the rounded atomic masses used in many school books (K = 39, Cl = 35.5, O = 16) the answer is 122.5 g/mol. The difference from 122.55 is too small to matter in most school sums.

Percentage composition

By mass, KClO3 is 31.91% potassium, 28.93% chlorine and 39.17% oxygen. The largest share comes from oxygen. In a 100 g sample there are 31.9 g of potassium, 28.9 g of chlorine and 39.2 g of oxygen.

Worked examples

Grams to moles. How many moles are in 5 g of KClO3? Divide the mass by the molar mass: 5 ÷ 122.55 = 0.0408 mol.

Moles to grams. What is the mass of 0.25 mol of KClO3? Multiply: 0.25 × 122.55 = 30.64 g.

Counting particles. 5 g contains 0.0408 mol × 6.022 × 1023 = 2.457 × 1022 formula units.

Making a solution. A 0.1 mol/L solution contains 0.1 × 122.55 = 12.25 g of KClO3 in each litre. For 250 mL, weigh 3.064 g and make it up to the mark with water.

Quick conversion tables

AmountMass
0.1 mol12.25 g
0.5 mol61.27 g
1 mol122.5 g
2 mol245.1 g
5 mol612.7 g
MassMoles
1 g0.00816 mol
10 g0.0816 mol
100 g0.816 mol
1 kg8.16 mol

For other amounts use the grams and moles converter.

Questions people ask

What is the molar mass of KClO3?

The molar mass of potassium chlorate (KClO3) is 122.55 g/mol, or 122.545 g/mol before rounding, using IUPAC abridged atomic weights.

How many moles are in 100 g of KClO3?

100 ÷ 122.55 = 0.816 mol.

What is the mass of one formula unit of KClO3?

Divide the molar mass by the Avogadro constant: 122.55 ÷ 6.022 × 1023 = 2.035 × 10-22 g.

What is the percentage of oxygen in KClO3?

Oxygen makes up 39.17% of the mass of KClO3: 3 × 15.999 ÷ 122.545 × 100.

Which values? This site uses the abridged standard atomic weights published by IUPAC (CIAAW), read on 12 November 2026. Your textbook or question paper may round them differently, for example H = 1 and O = 16, so its answer can differ slightly. In an exam, use the values the paper gives.

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