Molar MassMolar mass of chloroform (CHCl3)
The molar mass of chloroform, CHCl3, is 119.37 g/mol. One mole of it, which is 6.022 × 1023 molecules, has a mass of 119.37 grams.
119.37 g/mol
12.011 + 1.0080 + 3 × 35.45 = 119.369 · 5 atoms in the formula · also called trichloromethane
About chloroform
Chloroform is a heavy, sweet-smelling liquid once used as an anaesthetic and now as a solvent. Three chlorine atoms give almost nine tenths of its mass.
Other names: trichloromethane.
The working
The formula CHCl3 has 1 carbon atom, 1 hydrogen atom and 3 chlorine atoms, 5 atoms in all. Multiply each count by the atomic weight of the element and add:
| Element | Atoms | Atomic weight | Total | Share by mass |
|---|---|---|---|---|
| Carbon (C) | 1 | 12.011 | 12.011 | 10.06% |
| Hydrogen (H) | 1 | 1.0080 | 1.008 | 0.84% |
| Chlorine (Cl) | 3 | 35.45 | 106.350 | 89.09% |
12.011 + 1.0080 + 3 × 35.45 = 119.369 g/mol
With the rounded atomic masses used in many school books (C = 12, H = 1, Cl = 35.5) the answer is 119.5 g/mol. The difference from 119.37 is too small to matter in most school sums.
Percentage composition
By mass, CHCl3 is 10.06% carbon, 0.84% hydrogen and 89.09% chlorine. The largest share comes from chlorine. In a 100 g sample there are 10.1 g of carbon, 0.8 g of hydrogen and 89.1 g of chlorine.
Worked examples
Grams to moles. How many moles are in 40 g of CHCl3? Divide the mass by the molar mass: 40 ÷ 119.37 = 0.3351 mol.
Moles to grams. What is the mass of 3 mol of CHCl3? Multiply: 3 × 119.37 = 358.1 g.
Counting particles. 40 g contains 0.3351 mol × 6.022 × 1023 = 2.018 × 1023 molecules, and 1.009 × 1024 atoms in all.
Quick conversion tables
| Amount | Mass |
|---|---|
| 0.1 mol | 11.94 g |
| 0.5 mol | 59.68 g |
| 1 mol | 119.4 g |
| 2 mol | 238.7 g |
| 5 mol | 596.8 g |
| Mass | Moles |
|---|---|
| 1 g | 0.008377 mol |
| 10 g | 0.08377 mol |
| 100 g | 0.8377 mol |
| 1 kg | 8.377 mol |
For other amounts use the grams and moles converter.
Questions people ask
What is the molar mass of CHCl3?
The molar mass of chloroform (CHCl3) is 119.37 g/mol, or 119.369 g/mol before rounding, using IUPAC abridged atomic weights.
How many moles are in 100 g of CHCl3?
100 ÷ 119.37 = 0.8377 mol.
What is the mass of one molecule of CHCl3?
Divide the molar mass by the Avogadro constant: 119.37 ÷ 6.022 × 1023 = 1.982 × 10-22 g.
What is the percentage of chlorine in CHCl3?
Chlorine makes up 89.09% of the mass of CHCl3: 3 × 35.45 ÷ 119.369 × 100.
Which values? This site uses the abridged standard atomic weights published by IUPAC (CIAAW), read on 12 November 2026. Your textbook or question paper may round them differently, for example H = 1 and O = 16, so its answer can differ slightly. In an exam, use the values the paper gives.